Answer:
Step-by-step explanation:
hello :
g(x) = (x+2)(x-4)/(x+2)(x-1)
1 ) this function no exist for if : x= -2 and 1
so the denominater is : (x+2)(x-1)
so : b= 2 and c=1
2) the x- intercept is : 4
so the numerater is : (x+2)(x-4)
g(x) =0 if : (x+2)(x-4)=0
means x-4=0 ... ( x+2 ≠ 0)
note :
g(x) ≠ (x-4)/(x-1) except in the case x ≠ -2
