Answer:
Step-by-step explanation:
[tex]A+B=\theta\\B=\theta-A\\sin B=sin (\theta-A)\\sin A=\lambda[sin \theta cos A-cos \theta sin A]\\sin A[1+\lambda cos \theta]=cos A(\lambda sin \theta) \\\frac{sin A}{cosA} =\frac{\lambda sin \theta}{1+ \lambda cos \theta} \\[/tex]
[tex]tan A=\frac{\lambda sin \theta }{1+ \lambda cos \theta }[/tex]
