Answer:
[tex](3x+1)^2[/tex]
Step-by-step explanation:
[tex]9x^2+6x+1=\\(3x+1)^2[/tex]
You can confirm this by working and expanding backwards:
[tex](3x+1)^2=\\(3x+1)(3x+1)=\\9x^2+3x+3x+1=\\9x^2+6x+1[/tex]
Hope this helps!
(3x+1)^2
3x+1 • 3x +1 = (3x+1)^2
Distribute:
9x^2 +3x +3x +1 = 9x^2 +6x +1
