Answer:
The gradient of Line L = [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
The equation for K is:
=> 2y+3x-5 = 0
Arranging it in the form of slope-intercept equation:
=> [tex]y = -\frac{3}{2} x+\frac{5}{2}[/tex]
Since, Line L is perpendicular to Line K, The gradient of it would be the negative reciprocal of this gradient and multiplying both gives the result of -1.
So,
The gradient of Line L = [tex]\frac{2}{3}[/tex]
