Explanation:
It is required to find the electric force acting between two charges of -0.0080 C and 0.0050. Let the distance between them is r. So, the electrical force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
So,
[tex]F=\dfrac{9\times 9\times 0.0080\times 0.0050}{r^2}\\\\F=\dfrac{0.00324}{r^2}[/tex]
Hence, this is the required solution.
