[tex]\sqrt{3x+10}=\sqrt{2x+3}\\\\\\\dfrac{\sqrt{3x+10}}{\sqrt{2x+3}}=1\\\\\\\sqrt{\dfrac{3x+10}{2x+3}}=1\\\\\\\dfrac{3x+10}{2x+3}=1\\\\\\3x+10 =2x+3\\\\x = -7[/tex]
Answer:
x=-7
Step-by-step explanation:
first simplify your equation to:
3x+10=2x+3
combine like terms
3x-2x=3-10
solve for x
