Answer:
[tex]\large \boxed{\sf \ \ a = 2, \ b = -2, \ c = -3 \ \ }[/tex]
Step-by-step explanation:
Hello,
[tex]2x^2 - 8x + 5=2(x^2-4x)+5\\\\\text{*** We notice that *** }\\\\\text{*** } x^2-4x=(x-2)^2-2^2=(x-2)^2-4\\\\\text{*** So we can write ***}\\\\2x^2 - 8x + 5=2(x^2-4x)+5=2\left( (x-2)^2-4\right)+5\\\\=2\left(x-2\right)^2-8+5=\boxed{2\left(x-2\right)^2-3}[/tex]
So a = 2, b = -2, c = -3
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
