Answer:
[tex]\boxed{\sf 6.4 \ seconds}[/tex]
Step-by-step explanation:
t = time (s) ⇒ ?
d = distance falling (m) ⇒ 200 (m)
a = acceleration due to gravity ⇒ 9.8 (m/s²)
The time in seconds is not given. Solve for time using the formula.
[tex]t=\sqrt{\frac{2(200)}{9.8} }[/tex]
[tex]t=\sqrt{\frac{400}{9.8} }[/tex]
[tex]t= 6.388766...[/tex]
Round answer to nearest tenth of a second.
[tex]t \approx 6.4[/tex]
