Answer:
[tex] \boxed{ - 1}[/tex]
Step-by-step explanation:
The co-ordinates of B = ( 0 , a ) ⇒ ( x₁ , y₁ )
The co-ordinates of D = ( a , 0 )⇒( x₂ , y₂ )
Let's find the slope of BD
Slope = [tex] \mathrm{ = \frac{y2- y1}{x2 - x1} }[/tex]
[tex] \mathrm{ = \frac{0 - a}{a - 0} }[/tex]
[tex] \mathrm{ = \frac{ - a}{a} }[/tex]
[tex] \mathrm{ = - 1}[/tex]
[tex] \mathcal{HOPE \: I \: HELPED !}[/tex]
[tex] \mathcal{BEST \: REGARDS !}[/tex]
