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04-08-2020
Mathematics

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Given [tex]f(x)=-x^{2} +6x-11[/tex], find [tex]f(x-3)[/tex]

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04-08-2020

Answer:

See below.

Step-by-step explanation:

[tex]f(x)=-x^2+6x-11\\f(x-3)=-(x-3)^2+6(x-3)-11\\f(x-3)=-(x^2-6x+9)+6x-18-11\\f(x-3)=-x^2+6x-9+6x-29\\f(x-3)=-x^2+12x-38[/tex]

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