Answer:
[tex] x = \frac{6 \pm \sqrt{(-6)^2 - 4(3)(8)}}{2(3)} [/tex]
Step-by-step explanation:
Given the equation, [tex] 3x^2 - 6x + 8 = 0 [/tex], the quadratic formula for solving this equation is given as:
[tex] x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]
Where,
a = 3
b = -6
c = 8
Plug in the above values into the quadratic formula.
[tex] x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(3)(8)}}{2(3)} [/tex]
[tex] x = \frac{6 \pm \sqrt{(-6)^2 - 4(3)(8)}}{2(3)} [/tex]
