Answer:
The distance traveled by the particle after 1 second is 9m.
Explanation:
Given;
velocity of the particle, v = 4 m/s
acceleration of the particle, a = 10 m/s²
time of motion of the particle, t = 1 second
distance traveled by the particle, d = ?
The distance traveled by the particle is given by;
d = vt + ¹/₂at²
d = (4 x 1) + ¹/₂(10)(1)²
d = 9 m
Therefore, the distance traveled by the particle after 1 second is 9m.
