Answer:
(2x-1)
Step-by-step explanation:
[tex]Volume\ of\ the\ tank\ = 12x^3+20x^2-x-6\\Length\ of\ the\ tank\ = 3x+2\\Breadth\ of\ the\ tank\ = 2x+3\\Height\ of\ the\ tank\ = h\\We\ know\ that\ volume\ of\ a\ cuboid\ = lbh\\Hence, h= Volume / lb\\Here,\\Height\ of\ the\ tank= \frac{(12x^3+20x^2-x-6)}{(3x+2)(2x+3)} \\By\ factorising\ the\ volume\ through\ synthetic\ division\, \\we get,\\(12x^3+20x^2-x-6)= (3x+2)(2x+3)(2x-1)\\Hence, height= (2x-1)[/tex]
