Answer:
ae^ax+b
Step-by-step explanation:
If differentiating something with respect to x, or when finding the derivative on an expression in terms of x
First principal:
f'(x) = lim h → 0, f(x+h)-f(x)/h
f(x+h) = (x+h)^n
f'(x) = lim h → 0, (x+h)^n + x^n / h
Because the power rule states: d/dx[x^n} = nx^n-1.
So, d/dx [e^ax+b] = d/dx[ax+b] × e^ax+b = a × e^ax + b = ae^ax+b
