Answer:
y=8
Step-by-step explanation:
[tex]\frac{1}{3} x + \frac{1}{4}y= 1\\\\\frac{4x+3y}{12} =1\\4x+ 3y =12\\y = \frac{12-4x}{3}[/tex]
let's note this as our equation no. (i)
and let 2x-3y = -30 be the equation no. (ii)
Put value of y from (i) into (ii)
[tex]2x -3y = -30\\2x-3(\frac{12-4x}{3} )=-30\\2x -12+4x = -30\\6x = -30+12\\6x= -18\\x = -3[/tex]
Now put x = -3 back in equation (i)
[tex]y = \frac{12-4x}{3}\\y = \frac{12 - 4(-3)}{3}\\y = \frac{12 + 12}{3} \\y = 8[/tex]
