Answer:
D. 28°
Step-by-step explanation:
Since ∆FGH is congruent to ∆QRS, it follows that:
[tex] m\angle F = m\angle Q [/tex]
Thus:
[tex] 2x + 10 = 3x + 1 [/tex] (Substitution)
Collect like terms
[tex] 2x - 3x = -10 + 1 [/tex]
[tex] -x = -9 [/tex]
Divide both sides by -1
x = 9
[tex] \angle Q = 3x + 1 [/tex]
Plug in the value of x
[tex] \angle Q = 3(9) + 1 [/tex]
[tex] \angle Q = 28 degrees [/tex]
