Answer:
3y=x-1 OR y=⅓x-⅓
Step-by-step explanation:
Lets call the equation y=-3x+7 line l1
the other line passing through (4,1) l2
If two lines are perpendicular,then the product of their roots=-1
That is m(l1)×m(l2)=-1
Slope of l1=-3 therefore slope of l2=-1÷-3=⅓
Now that we have determined the slope of l2 we move on to find it's equation using the point-slope form
y-y1=m(x-x1)
y-1=⅓(x-4)
3y-3=x-4
3y=x-4+3
3y=x-1 OR y=⅓x-⅓
