Answer:
(c)
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0
Then the product of the roots = [tex]\frac{c}{a}[/tex]
(k - 2)x² - 6x + 12 = 0 ← is in standard form
with a = k - 2 and c = 12 , thus
[tex]\frac{12}{k-2}[/tex] = 3 ( multiply both sides by (k - 1) )
12 = 3(k - 2) = 3k - 6 ( add 6 to both sides )
18 = 3k ( divide both sides by 3 )
6 = k → (c)
