Answer:
x=2, x=-2, and x=-1
Step-by-step explanation:
Function: f(x)=(x-2)(x+2)(x+1)²
We can solve each one of the zeros by making the expressions (the ones in the parentheseis) equal zero.
So we have three equations:
1.(x-2)=0
2.(x+2)=0
3.(x+1)²=0
Solve.
1.x-2=0
x=2
2. x+2=0
x=-2
3. (x+1)²=(x+1)(x+1)=0
(x+1)=0
x=-1
(x+1)=0
x=-1
Since those two were the same we can just say x=-1 once.
Here are the three zeros:
x=2, x=-2, and x=-1
hope this helps!
