Answer:
[tex]\huge\boxed{4x+15}[/tex]
Step-by-step explanation:
[tex]4(6-2x)-3(3-4x)\qquad|\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(4)(6)+(4)(-2x)+(-3)(3)+(-3)(-4x)\\\\=24-8x-9+12x\qquad|\text{combine like terms}\\\\=(-8x+12x)+(24-9)\\\\=4x+15[/tex]
