Answer:
3
Step-by-step explanation:
The average rate of change of h(x) in the closed interval [ a, b ] is
[tex]\frac{h(b)-h(a)}{b-a}[/tex]
Here [ a, b ] = [ 1, 2 ], then from the table
h(b) = h(2) = 0
h(a) = h(1) = - 3 , then
average rate of change = [tex]\frac{0-(-3)}{2-1}[/tex] = [tex]\frac{3}{1}[/tex] = 3
