Answer:
Halved
Explanation:
F=ma
Let case 1 (original) be:
[tex]F_{1}=m_{1} a_{1} \\[/tex]
Case 2 (new) be:
[tex]F_{2}=m_{2} a_{2}[/tex]
Mass is double:
[tex]m_{2}= 2m_{1}[/tex]
Force kept the same:
[tex]F_{1} =F_{2}[/tex]
Combine the equation and gives:
[tex]\frac{F_{1} }{F_{2}} =\frac{m_{1} a_{1} }{m_{2}a_{2} }\\\frac{F_{1} }{F_{1}} =\frac{m_{1} a_{1} }{2m_{1}a_{2} }\\1=\frac{a_{1} }{2a_{2} }\\a_{2}=\frac{1}{2} a_{1}[/tex]
Acceleration is halved
