We know , [tex]1 \ rpm = \dfrac{2\pi}{60}\ rad/s[/tex]
So, [tex]20 \rpm = 20\times \dfrac{2\pi}{60} = \dfrac{2\pi}{3}\ rad/s\\[/tex]
It is also given that, boy sits 1.0 meters away from the center of the merry go round.
Solution :
We know, velocity of at distance r from center in a circular body is given by :
[tex]velocity = \omega \times r\\\\velocity = \dfrac{2\pi}{3}\times 1 \\\\velocity = \dfrac{2\pi}{3}\\\\velocity = 2.09\ m/s[/tex]
Therefore, the velocity of boy is 2.09 m/s.
