Answer:
f(x) = -2(x-3)^2+8
Step-by-step explanation:
Using vertex form: f(x)= a(x-h)^2 +k
if the maximum is 8 then k=8
h = 3 --> the midpoint of 1 and 5
Fill in the equation:
f(x) = a(x-3)^2 +8
Using f(1) = 0 to figure out a:
0 = a(1-3)^2+8
4a =-8
a = -2
Our final equation would be[tex]f(x)=-2(x-3)^2+8[/tex]
In standard form: [tex]f(x)=-2x+12x-10[/tex]
