Answer:
[tex]\%m/m=33.0\%[/tex]
Explanation:
Hello there!
In this case, since the percent by mass of a solute in a solution is computed via the following division:
[tex]\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%[/tex]
Next, given the mass of HCl and that of water, we plug them in to obtain:
[tex]\%m/m=\frac{22.5g}{22.5g+45.8g} *100\%\\\\\%m/m=33.0\%[/tex]
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