Answer:
15.4 g
Explanation:
The reaction that takes place is:
- 2C₅H₁₀ + 15O₂ → 10CO₂ + 10H₂O
First we convert 5 grams of C₅H₁₀ into moles, using its molar mass:
- 5 g ÷ 70 g/mol = 0.07 mol C₅H₁₀
Then we convert C₅H₁₀ moles into CO₂ moles, using the stoichiometric coefficients of the reaction:
- 0.07 mol C₅H₁₀ * [tex]\frac{10molCO_2}{2molC_5H_{10}}[/tex] = 0.35 mol CO₂
Finally we convert 0.35 moles of CO₂ into grams:
- 0.35 mol CO₂ * 44 g/mol = 15.4 g
