Answer:
[tex]m_{powder}=433g[/tex]
Explanation:
Hello there!
In this case, according to the composition of the black powder - 75% potassium nitrate, 15% charcoal and 10% sulfur, we can see that starting by 65.0 grams of charcoal, the produced amount of the black powder would be:
[tex]15.0\%=\frac{m_{charcoal}}{m_{powder}} *100\%\\\\m_{powder}=\frac{m_{charcoal}}{15.0\%} *100\%\\\\m_{powder}=\frac{65.0g}{15.0\%} *100\%\\\\m_{powder}=433g[/tex]
Best regards!
