Answer:
[tex]11\sqrt{797}\pi[/tex]
Step-by-step explanation:
[tex]A=\pi r \sqrt{h^2+r^2}[/tex]
the radius is 22/2 = 11 in
h is 26 in
substitute: [tex]\pi \left(11\right)\sqrt{\left(26^2\right)+\left(11^2\right)}[/tex]
= [tex]11\sqrt{797}\pi[/tex]
286π in²
The lateral area (A) of the cone is calculated as
A = πrs ( r is the radius and s the slant height )
Here r = 22 ÷ 2 = 11 and s = 26 , then
A = π × 11 × 26 = 286π in²
