Answer:
The answer is "[tex]0.13562748[/tex]"
Explanation:
Please find the complete question in the attached file.
Using formula:
[tex]\bold{U_s=\frac{v^2}{rg}}[/tex]
Given:
[tex]r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}[/tex]
put the value into the above-given formula:
[tex]U_s= \frac{14.583^2}{160 \times 9.8}[/tex]
[tex]= \frac{212.663889}{1568}\\\\=0.13562748[/tex]
