Answer:
the volume is 18.45 L
Explanation:
The computation of the volume when the temperature is increased to 60.0 K is shown below:
Since the gas occupied 12.3 L at a temperature of 40.0 k
And, the volume when the new temperature is 60.0 k
So, the volume is
= 60.0 k × 12.3 L ÷ 40.0 k
= 18.45 L
hence, the volume is 18.45 L
