Answer:
63.7 °C
Explanation:
Step 1: Given and required data
- Mass of water (m): 75.4 g
- Initial temperature (T₁): 12.6 °C
- Absorbed heat (Q): 3.85 kcal
- Specific heat capacity of water (c): 1 cal/g.°C
Step 2: Calculate the final temperature of the water (T₂)
We will use the following expression.
Q = c × m × (T₂ - T₁)
T₂ = Q/c × m + T₁
T₂ = 3.85 × 10³ cal/(1 cal/g.°C) × 75.4 g + 12.6 °C = 63.7 °C
