Answer:
AB= [tex]\sqrt(5-1)^2 +(2+1)^2 = \sqrt16+9 =5[/tex]
BC= [tex]\sqrt(5-9)^2 + (2-5)^2 = \sqrt16+9=5[/tex]
AC = [tex]\sqrt(1-9)^2 + (-1-5)^2 = \sqrt64+36 = 10[/tex]
So, AC = AB + BC
A, B, C are collinear points
Step-by-step explanation:
I hope this helps!
