Answer:
Let p (x) = x + 1 / x = 2
= x + 1 = 2x
= 2x - x = 1
or, x = 1.
let g(x) = x^3 + 1/x^3
since, x = 1
therefore,
g (1) = (1)^3 +1 / (1)^3
= 1 + 1 / 1
= 2 / 1
= 2
So, the answer to your question is 2.
x + 1 / x = 2
x × ( x + 1 / x ) = x × 2
x + 1 = 2x
x - x + 1 = 2x - x
x = 1
_________________________________
x^3 + 1 / x^3 =
1^3 + 1 / 1^3 =
1 + 1 / 1 =
2 / 1 =
2
