Answer:
28.55 mL or 0.02855 L
Explanation:
Applying,
Density(D) = mass(m)/Volume(V)
D = m/V............... Equation 1
Where D = Density of the Bromine, m = mass of the bromine, V = volume of the bromine
make V the subeject of the equation
V = m/D............. Equation 2
From the question,
Given: m = 88.5 g, D = 3.10 g/mL
Substitute these values into equation 2
V = 88.5/3.10
V = 28.55 mL
Hence the volume occuppied by the Bromine gas is 28.55 mL or 0.02855 L
