Answer:
[tex]\sqrt{13}[/tex]
Step-by-step explanation:
Given a vector < x, y > then its magnitude is
[tex]\sqrt{x^2+y^2}[/tex]
Given the directed line segment
P (0, 0 ) → Q (3, 2 ) then
PQ = q - p = (3, 2 ) - (0, 0 ) = < 3 - 0, 2 - 0 > = < 3 , 2 >
| PQ | = [tex]\sqrt{3^2+2^2}[/tex] = [tex]\sqrt{9+4}[/tex] = [tex]\sqrt{13}[/tex]
