Answer:
[tex]4^{-5}[/tex]
Step-by-step explanation:
The given expression is :
[tex]4^{-3}\times (\dfrac{1}{4})^2[/tex]
We know that, [tex]x^{-a}=\dfrac{1}{x^a}[/tex]
So,
[tex]4^{-3}\times (\dfrac{1}{4})^2=\dfrac{1}{4^3}\times (\dfrac{1}{4})^2\\\\=\dfrac{1}{4^3}\times \dfrac{1}{4^2}\\\\=\dfrac{1}{4^3\times 4^2}\\\\=\dfrac{1}{4^{3+2}}\\\\=\dfrac{1}{4^5}\\\\=4^{-5}[/tex]
So, the answer of the given expression is equal to [tex]4^{-5}[/tex].
