Answer:
Explanation:
The formula for the magnitude of a vector is
[tex]B_{mag}=\sqrt{(-1.33)^2+(2.81)^2}[/tex] and then round to the hundredths place:
3.11 m. Since we are in Q2, we can also find the direction of this vector:
[tex]tan^{-1}(\frac{2.81}{-1.33})=-64.7[/tex] but since we are in Q2, we add 180 degrees to the result, getting the angle to be 115.3
