Answer:
[tex]y=\dfrac{-3}{7}x-\dfrac{32}{7}[/tex]
Step-by-step explanation:
Given that,
A line 7x - 3y = 68 and containing the point (8, -8).
The equation can be written as :
[tex]-3y=68-7x\\\\y=\dfrac{68}{-3}+\dfrac{7x}{3}\\\\y=\dfrac{7x}{3}+(\dfrac{-68}{3})[/tex]
The slope is :7/3
Line is perpendicular so use m = –3/7
[tex]-8=(-\dfrac{3}{7})\times 8+b\\\\-8+\dfrac{3}{7}\times 8=b\\\\b=\dfrac{-32}{7}[/tex]
So, required equation is :
[tex]y=\dfrac{-3}{7}x-\dfrac{32}{7}[/tex]
