Step-by-step explanation:
Hi there!
Given;
Point Q is located at (-4, 6). Point R is located at (8, 6).
Note: Use distance formula.
Now;
[tex](d) = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]
Keep all values;
[tex](d) = \sqrt{ {(8 + 4)}^{2} + ( {6 - 6)}^{2} } [/tex]
Simplify;
[tex](d) = \sqrt{( {12)}^{2} } [/tex]
Therefore, the distance is 12 units.
Hope it helps!
