9514 1404 393
Answer:
x = -2 ±i(√6)/3
Step-by-step explanation:
The formula for the solution of ax²+bx+c=0 is ...
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
When your equation is written in standard form, it is ...
3x² +12x +14 = 0
so the values needed in the formula are a=3, b=12, c=14.
[tex]x=\dfrac{-12\pm\sqrt{12^2-4(3)(14)}}{2(3)}=\dfrac{-12\pm\sqrt{-24}}{6}=\dfrac{-12\pm2i\sqrt{6}}{6}\\\\\boxed{x=-2\pm\dfrac{\sqrt{6}}{3}i}[/tex]
