Answer:
a = [tex]\frac{13}{5}[/tex]
Step-by-step explanation:
Given
a = [tex]\frac{3x+2y}{3x-2y}[/tex] , substitute y = 4 , x = 6
a = [tex]\frac{3(6)+2(4)}{3(6)-2(4)}[/tex] = [tex]\frac{18+8}{18-8}[/tex] = [tex]\frac{26}{10}[/tex] = [tex]\frac{13}{5}[/tex]
