Answer:
[tex]-6x+14<-28[/tex]
[tex]-6x<-28-14[/tex]
Add,
[tex]-6x<-42[/tex]
Divide both sides by 6
[tex]\frac{6x}{6}>\frac{42}{6}[/tex]
[tex]x>7[/tex]
[tex]3x+28\leq 25[/tex]
Subtract both sides by 28
[tex]3x\le \:-3[/tex]
Now, divide both sides by 3
[tex]x\le \:-1[/tex]
Answer:- [tex]x\leq -1\: or \: x>7[/tex]
OAmalOHopeO
