Answer:
We know that a(1)=1
a(1)=3*1(1-1)=3*1*0=3*0=0 (any no.multiplied by 0 is equal to 0)
a(2)=3*2(2-1)=3*2*1=6*1=6
Similarly,
a(3)=18
a(4)=36
a(5)=60
Hence, the first five terms of sequence a(n)=3*a(n-1), where a(1)=1 are 0,6,18,36,60.
Thanks for reading.
