Answer:
[tex]\sqrt{x-\sqrt{1-x}} = 1 - \sqrt{x} \\x-\sqrt{1-x} = 1 - 2\sqrt{x} +x\\-\sqrt{1-x} = 1 - 2\sqrt{x}\\1-x = 1 - 4\sqrt{x} + 4x\\-x = -4 \sqrt{x} + 4x\\4\sqrt{x} = 4x + x\\4\sqrt{x} = 5x\\16x = 25x^{2} \\16x - 25x^{2} = 0\\x (16 - 25x) = 0\\[/tex]
x ≠ 0, it can't be 0.
x = [tex]\frac{16}{25}[/tex]
