9514 1404 393
Answer:
1 +x -x^2/2 +x^3/2 -5x^4/8+7x^5/8
Step-by-step explanation:
We can use the expansion formula shown in the attachment. Here, we have a=1, b=2x, so the expansion is ...
[tex]\sqrt{1}+\dfrac{2x}{2\sqrt{1}}-\dfrac{(2x)^2}{8(1\sqrt{1})}+\dfrac{(2x)^3}{16(1\sqrt{1})}-\dfrac{5(2x)^4}{128(1\sqrt{1})}+\dfrac{7(2x)^5}{256(1\sqrt{1})}\\\\=\boxed{1+x-\dfrac{x^2}{2}+\dfrac{x^3}{2}-\dfrac{5x^4}{8}+\dfrac{7x^5}{8}}[/tex]
