Answer:
[tex]a=8,-11[/tex]
Step-by-step explanation:
[tex]a^2=-3a+88[/tex]
[tex]a^2+3a=88[/tex]
[tex]a^2+3a-88=0[/tex]
[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
[tex]x=\frac{-3\pm\sqrt{3^2-4(1)(-88)} }{2(1)}[/tex]
[tex]x=\frac{-3\pm\sqrt{9+352} }{2}[/tex]
[tex]x=\frac{-3\pm\sqrt{361} }{2}[/tex]
[tex]x=\frac{-3\pm19 }{2}[/tex]
[tex]x=-11[/tex] and [tex]x=8[/tex]
Therefore, the values of [tex]a[/tex] are 8 and -11.
