Answer:
3/4 of a mol of Rust
Explanation:
The first thing you have to do is work from a balanced equation.
4Fe + 3O2 ====> 2Fe2O3
Left
4 Fe
6 Oxygens
Right
4Fe
2*3 = 6 Oxygens
So you have a balanced equation
4Fe + 3O2 ====> 2Fe2O3
1.5 x
The next (and last) thing to do is to set up a proportion
4/1.5 = 2/x Cross multiply
4x = 1.5*2 Combine
4x = 3 Divide by 4
4x/4 = 3/4
x = 3/4 mol
