Answer:
[tex](10, 2)[/tex]
Step-by-step explanation:
Reflecting a point [tex](x, y)[/tex] over the line [tex]x=3[/tex] gives the point [tex](x-2(x-3), y)[/tex], which simplifies to [tex](-x+6, y)[/tex].
Plugging in the point [tex](-4, 2)[/tex] to the equation gives the reflected point [tex]A'[/tex], which is at [tex](-(-4)+6, 2)=(10, 2)[/tex]
