Answer:
[tex]6[/tex]
Step-by-step explanation:
We see that the triangle is a right triangle. We need to find the lengths of the two legs to find the area, then. Let's start with AB.
[tex]AB=\sqrt{(3-1)^2+(0-(-2))^2}=\sqrt{2^2+2^2}=\sqrt{8}=2\sqrt{2}[/tex]
Now, we do the other leg.
[tex]\sqrt{(1-4)^2+(-2-(-5))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}[/tex].
That will make the area [tex]b*h/2=2\sqrt{2}*3\sqrt{2}/2=6*2/2=6[/tex]
