Answer:
Solution given:
2:centroid=[tex]\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}[/tex]
=[tex]\frac{1+3+5}{3},\frac{2+7+3}{3}=(3,4)[/tex]
4:
Slope:[tex]\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{5-3}=2[/tex]
3;
perpendicular distance =[tex]\frac{ax_1+by_1+c}{\sqrt{a²+b²}}[/tex]
[tex](x_1,y_1)=(3,-2)[/tex]
4x-3y+2=0
comparing above equation with ax+by+c =0 ,we get
a=4
b=-3
c=2
d=[tex]\frac{4*3+(-3*-2)+2}{\sqrt{4²+(-3)²}}[/tex]
=4 units
